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480-x^2-4x=0
We add all the numbers together, and all the variables
-1x^2-4x+480=0
a = -1; b = -4; c = +480;
Δ = b2-4ac
Δ = -42-4·(-1)·480
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-44}{2*-1}=\frac{-40}{-2} =+20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+44}{2*-1}=\frac{48}{-2} =-24 $
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